JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    The correct match between items of List-I and List-II is?                                 [JEE Online 15-04-2018]
    List-I List-II
    (A) Coloured impurity (P) Steam distillation
    (B) Mixture of O-nitrophenol and p-nitrophenol (Q) Fractical distillation
    (C) Crude Naphtha (R) Charcoal treatment
    (D) Mixture of glycerol and sugars (S) Distillation under reduced pressure.

    A) (A)-(R), (B)-(S), (C)-(P), (D)-(Q)

    B) (A)-(R), (B)-(P), (C)-(S), (D)-(Q)

    C) (A)-(P), (B)-(S), (C)-(R), (D)-(Q)

    D) (A)-(R), (B)-(P), (C)-(Q), (D)-(S)

    Correct Answer: D

    Solution :

    (A) Charcoal treatment removes coloured impurity through adsorption.
    (B) Steam distillation separates the mixture of o-nitrophenol and p-nitrophenol. The o-nitrophenol is steam volatile (due to intramolecular hydrogen bonding), and the para isomer is not volatile.
    (C) Fractional distillation separates Crude Naphtha. Naphtha is a flammable liquid hydrocarbon mixture.
    (D) Distillation under reduced pressure separates mixture of glycerol and sugars. Vacuum distillation lowers the boiling point and prevents decomposition.


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