JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridisation are respectively _________.                                                                             [JEE Online 15-04-2018]

    A) \[\text{50}\,\,\text{and}\,\,\text{75}\]             

    B) \[\text{67}\,\,\text{and }\,\,\text{75}\]

    C)        \[\text{33}\,\,\text{and 25}\]               

    D) \[\text{33}\,\,\text{and}\,\,\text{75}\]

    Correct Answer: B

    Solution :

    \[\text{ }\!\!%\!\!\text{ p-characters}\] \[\text{=}\frac{\text{p-orbitals}}{\text{total orbitals}}\] \[\text{s}{{\text{p}}^{2}}\] in graphite \[\text{s}{{\text{p}}^{3}}\] diamond \[\therefore \] for Graphite, \[%p-characters=\frac{2}{3}\times 100\]                                                 \[=67%\] For diamond, % p-characters \[=\frac{3}{4}\times 100\]                                                 \[75%\]


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