JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    The equivalent capacitance between A and B  in the circuit given below is: [JEE Online 15-04-2018]

    A) \[4.9\mu F\]                

    B) \[3.6\mu F\]    

    C) \[5.4\mu F\]                

    D) \[2.4\mu F\]    

    Correct Answer: D

    Solution :

    \[{{C}_{1}}=5+5+2=12\mu F\] \[{{C}_{2}}=4+2=6\mu F\] \[1/{{C}_{Eq}}=1/6+1/12+1/6=5/12\] \[{{C}_{Eq}}=2.4\mu F\]


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