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JEE Main & Advanced JEE Main Paper (Held On 12 May 2012)

  • question_answer
    Given (i)\[HCN(aq)+{{H}_{2}}O(l){{H}_{3}}{{O}^{+}}(aq)+C{{N}^{-}}(aq)\]\[{{K}_{a}}=6.2\times {{10}^{-10}}\] (ii)\[C{{N}^{-}}(aq)+{{H}_{2}}O(l)HCN(aq)+O{{H}^{-}}(aq)\] \[{{K}_{b}}=1.6\times {{10}^{-5}}.\] These equilibria show the following order of the relative base strength,     JEE Main Online Paper (Held On 12 May 2012)

    A) \[OH>{{H}_{2}}O>C{{N}^{-}}\]

    B)                        \[O{{H}^{-}}>C{{N}^{-}}>{{H}_{2}}O\]

    C)                        \[{{H}_{2}}O>C{{N}^{-}}>O{{H}^{-}}\]

    D)                        \[C{{N}^{-}}>{{H}_{2}}O>O{{H}^{-}}\]

    Correct Answer: B

    Solution :

                    The more is the value of equilibrium constant, the more is the completion of reaction or more is the concentration of products i.e. the order of relative strength would be. \[O{{H}^{-}}>C{{N}^{-}}>{{H}_{2}}O\]


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