A) \[4\pi {{a}_{0}}\]
B) \[8\pi {{a}_{0}}\]
C) \[6\pi {{a}_{0}}\]
D) \[2\pi {{a}_{0}}\]
Correct Answer: C
Solution :
\[{{r}_{n}}={{a}_{0}}{{n}^{2}}\] \[r={{a}_{0}}\times {{(3)}^{2}}=9{{a}_{0}}\] \[mvr=\frac{nh}{2\pi };\] \[mv=\frac{nh}{2\pi r}=\frac{3h}{2\pi \times 9{{a}_{0}}}=\frac{h}{6\pi {{a}_{0}}}\] \[\lambda =\frac{h}{mv}=\frac{n}{h}\times 6\pi {{a}_{0}}=6\pi {{a}_{0}}\]
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