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JEE Main & Advanced JEE Main Paper (Held On 12 May 2012)

  • question_answer
    An aqueous solution of oxalic acid dehydrate contains its 6.3 g in 250 ml. The volume of 0.1N NaOH required to completely neutralize 10 ml of this solution     JEE Main Online Paper (Held On 12 May 2012)

    A) 4ml                                        

    B)                        20ml

    C)                        2ml                                        

    D)                        40ml

    Correct Answer: D

    Solution :

                    Normality of oxalic acid solution \[=\frac{6.3\times 1000}{63\times 250}=0.4N\]Now from \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[0.4\times 10=0.1\times {{V}_{2}}\] \[{{V}_{2}}=40mL\]


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