JEE Main & Advanced JEE Main Paper (Held On 12 May 2012)

  • question_answer
    The magnetic force acting on charged particle of charge \[2\mu C\]in magnetic field of 2 F acting in y-direction, when the particle velocity is \[\left( 2\hat{i}+3\hat{j} \right)\times {{10}^{6}}m{{s}^{-1}}\]is   JEE Main Online Paper (Held On 12 May 2012)

    A) 8 N in z-direction             

    B)                        8 N in y-direction

    C)                        4 N in y-direction             

    D)                        4 N in z-direction

    Correct Answer: A

    Solution :

                    \[\overset{\to }{\mathop{F}}\,=q\left( \overset{\to }{\mathop{V}}\,\times \overset{\to }{\mathop{B}}\, \right)\] \[=2\times {{10}^{-6}}\left[ (2\hat{i}+3\hat{j})\times {{10}^{6}}\times 2\hat{j} \right]\] \[=2\times 4\hat{k}=8N\]in Z-direction.


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