JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Morning)

  • question_answer
    A ratio of the \[{{5}^{th}}\] term from the beginning to the \[{{5}^{th}}\] term from the end in the binomial is expansion of \[{{\left( {{2}^{1/3}}+\frac{1}{2{{(3)}^{1/3}}} \right)}^{10}}\] is [JEE Main Online Paper Held On 12-Jan-2019 Morning]

    A) \[4{{(36)}^{1/3}}:1\]                           

    B) \[1:2{{(6)}^{1/3}}\]

    C) \[2{{(36)}^{1/3}}:1\]               

    D)   \[1:4{{(16)}^{1/3}}\]

    Correct Answer: A

    Solution :

    In the expansion\[{{\left( {{2}^{1/3}}+\frac{1}{2{{(3)}^{1/3}}} \right)}^{10}}\]the ratio of \[{{5}^{th}}\] term from the beginning to the \[{{5}^{th}}\] term from the end =\[\frac{^{10}{{C}_{4}}{{({{2}^{1/3}})}^{10-4}}{{\left( \frac{1}{2{{(3)}^{1/3}}} \right)}^{4}}}{^{10}{{C}_{4}}{{\left( \frac{1}{2{{(3)}^{1/3}}} \right)}^{10-4}}{{({{2}^{1/3}})}^{4}}}=\frac{4.{{(36)}^{1/3}}}{1}\]


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