question_answer

The major product of the following reaction is \[C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\xrightarrow[(ii)\,\,NaN{{H}_{2}}in\,liq.N{{H}_{3}}]{(i)\,KOH\,alc.}\] [JEE Main Online Paper Held On 12-Jan-2019 Evening]

A) \[C{{H}_{3}}CH=C=C{{H}_{2}}\]                 

B) \[C{{H}_{3}}C{{H}_{2}}C\equiv CH\]

C) \[C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix}  | \\  N{{H}_{2}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix}  | \\  N{{H}_{2}} \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\]              

D) \[C{{H}_{3}}CH=CHC{{H}_{2}}N{{H}_{2}}\]

Correct Answer: B

Solution :