A) \[{{10}^{-2}}T\]
B) \[1T\]
C) \[{{10}^{-4}}T\]
D) \[{{10}^{2}}T\]
Correct Answer: C
Solution :
Mean intensity \[=\frac{B_{rms}^{2}}{{{\mu }_{0}}}c\] \[\Rightarrow \]\[B_{rms}^{2}=\frac{{{10}^{8}}\times 4\pi \times {{10}^{-7}}}{3\times {{10}^{8}}}\] \[B_{rms}^{{}}\approx {{10}^{-4}}T\]
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