A) second and third quadrants only
B) third and fourth quadrants only
C) first, third and fourth quadrants
D) first, second and fourth quadrants
Correct Answer: B
Solution :
\[2y=2\sin x\sin \left( x+2 \right)2{{\sin }^{2}}\left( x+1 \right)\] \[2y=cos2cos\left( 2x+2 \right)\left( 1cos\left( 2x+2 \right) \right)\] \[=cos21\] \[2y=-2{{\sin }^{2}}\frac{1}{2}\] \[y=-{{\sin }^{2}}\frac{1}{2}\le 0\]
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