2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Morning)

  • question_answer
    For \[x\in R,\]let [x] denote the greatest integer \[\le x,\] then the sum of the series \[\left[ -\frac{1}{3} \right]+\left[ -\frac{1}{3}-\frac{1}{100} \right]+\left[ -\frac{1}{3}-\frac{2}{100} \right]+.....+\left[ -\frac{1}{3}-\frac{99}{100} \right]\]is                  [JEE Main Held on 12-4-2019 Morning]

    A) -153    

    B) -133

    C) -131                

    D) -135

    Correct Answer: B

    Solution :

    \[\underbrace{\left[ -\frac{1}{3} \right]+\left[ -\frac{1}{3}-\frac{1}{100} \right]+.....+\left[ -\frac{1}{3}-\frac{66}{100} \right]}_{(-1)67}\]           \[+\underbrace{\left[ -\frac{1}{3}-\frac{67}{100} \right]+.....+\left[ -\frac{1}{3}-\frac{99}{100} \right]}_{-2(33)}=-133\]


You need to login to perform this action.
You will be redirected in 3 sec spinner