JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Morning)

  • question_answer
    A point dipole \[\vec{p}=-{{p}_{0}}\hat{x}\]is kept at the origin. The potential and electric field due to this dipole on the y-axis at a distance d are, respectively:                         [JEE Main Held on 12-4-2019 Morning]
    (Take V = 0 at infinity):

    A) \[\frac{|\vec{p}|}{4\pi {{\varepsilon }_{0}}{{d}^{2}}},\frac{-\vec{p}}{4\pi {{\varepsilon }_{0}}{{d}^{3}}}\]           

    B) \[0,\frac{{\vec{p}}}{4\pi {{\varepsilon }_{0}}{{d}^{3}}}\]

    C) \[\frac{|\vec{p}|}{4\pi {{\varepsilon }_{0}}{{d}^{3}}},\frac{{\vec{p}}}{4\pi {{\varepsilon }_{0}}{{d}^{3}}}\]           

    D) \[0,\frac{-\vec{p}}{4\pi {{\varepsilon }_{0}}{{d}^{3}}}\]

    Correct Answer: D

    Solution :

    \[V=0\] \[E=-\frac{K\vec{P}}{{{r}^{3}}}\] \[=-\frac{{\vec{p}}}{4\pi {{\varepsilon }_{0}}{{d}^{3}}}\]


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