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JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Morning)

  • question_answer
    Let \[{{S}_{n}}\]denote the sum of the first n terms of an A.P. If \[{{S}_{4}}=16\]and \[{{S}_{6}}=-48,\]then\[{{S}_{10}}\]is equal to: [JEE Main Held on 12-4-2019 Morning]

    A) -320

    B) -260

    C) -380                

    D) -410

    Correct Answer: A

    Solution :

                     \[2\left\{ 2a+3d \right\}=16\] \[3\left( 2a+5d \right)=48\] \[2a+3d=8\] \[2a+5d=16\] \[\] \[{{S}_{10}}=5\{44-9\times 12\}\] \[=-320\]


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