JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Morning)

  • question_answer
    The basic structural unit of feldspar, zeolites, mica, and asbestos is:   [JEE Main Held on 12-4-2019 Morning]

    A) \[{{(Si{{O}_{3}})}^{2-}}\]                       

    B) \[Si{{O}_{2}}\]

    C) \[{{(Si{{O}_{4}})}^{4-}}\]           

    D)

    Correct Answer: C

    Solution :

    Fledespar \[KAlS{{i}_{3}}{{O}_{8}}-NaAlS{{i}_{3}}{{O}_{8}}-CaA{{l}_{2}}S{{i}_{2}}{{O}_{8}}\] Zeolites \[-NaAlS{{i}_{3}}{{O}_{6}}.{{H}_{2}}O\] mica \[-KA{{l}_{3}}S{{i}_{3}}{{O}_{10}}{{(OH)}_{2}}\] asbestos \[-M{{g}_{3}}S{{i}_{2}}{{O}_{5}}{{(OH)}_{4}}\] These all are silicates having basic unit \[{{(Si{{O}_{4}})}^{4-}}\]         


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