2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Morning)

  • question_answer
    An element has a face-centred cubic (fcc) structure with a cell edge of a. The distance between the centres of two nearest tetrahedral voids in the lattice is:         [JEE Main Held on 12-4-2019 Morning]

    A) \[\frac{a}{2}\]

    B) \[a\]

    C) \[\frac{3}{2}a\]                                  

    D) \[\sqrt{2}a\]

    Correct Answer: A

    Solution :

    Distance between two nearest tetrahedral void\[=\left( \frac{a}{2} \right)\]              


You need to login to perform this action.
You will be redirected in 3 sec spinner