question_answer

The resistive network shown below is connected to a D.C. source of 16V. The power consumed by the network is 4 Watt. The value of R is :                               [JEE Main Held on 12-4-2019 Morning]

A) \[8\Omega \]   

B) \[6\Omega \]

C) \[1\Omega \]               

D) \[16\Omega \]

Correct Answer: A

Solution :

\[P=\frac{{{16}^{2}}}{8R}=4\therefore R=8\Omega \]