A) \[Ca{{(HC{{O}_{3}})}_{2}}\]and\[CaO\]
B) \[Mg{{(HC{{O}_{3}})}_{2}}\]and\[MgC{{O}_{3}}\]
C) \[Mg{{(HC{{O}_{3}})}_{2}}\]and\[Mg{{(OH)}_{2}}\]
D) \[Ca{{(HC{{O}_{3}})}_{2}}\]and\[Ca{{(OH)}_{2}}\]
Correct Answer: C
Solution :
Temporary hardness is due to soluble \[Mg{{(HC{{O}_{3}})}_{2}}\]and\[Ca{{(HC{{O}_{3}})}_{2}}\] \[Mg{{(HC{{O}_{3}})}_{2}}\xrightarrow[{}]{Boil}Mg{{(OH)}_{2}}\downarrow +2C{{O}_{2}}\uparrow \] \[Ca{{(HC{{O}_{3}})}_{2}}\xrightarrow[{}]{Boil}CaC{{O}_{3}}\downarrow +{{H}_{2}}O+C{{O}_{2}}\uparrow \]
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