A) \[\frac{{{b}^{2}}\tau }{4}\]
B) \[\frac{{{b}^{2}}\tau }{2}\]
C) \[{{b}^{2}}\tau \]
D) \[\frac{{{b}^{2}}\tau }{\sqrt{2}}\]
Correct Answer: B
Solution :
\[\text{v}=b\sqrt{x}\] \[\frac{d\text{v}}{dt}=\frac{b}{2\sqrt{x}}\frac{dx}{dt}\] \[a=\frac{b\text{v}}{2\sqrt{x}}\] \[a=\frac{b\left( b\sqrt{x} \right)}{2\sqrt{x}}\] \[\frac{d\text{v}}{dt}=a=\frac{{{b}^{2}}}{2}\] \[\text{v}=\frac{{{b}^{2}}}{2}\tau \]
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