JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Afternoon)

  • question_answer
    A tuning fork of frequency 480 Hz is used in an experiment for measuring speed of sound (v) in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, \[{{l}_{1}}=30cm\]and \[{{l}_{2}}=70cm\]. Then n is equal to : [JEE Main 12-4-2019 Afternoon]

    A) \[332m{{s}^{-1}}\]             

    B) \[379m{{s}^{-1}}\]

    C) \[384m{{s}^{-1}}\]

    D)   \[338m{{s}^{-1}}\]

    Correct Answer: C

    Solution :

                \[\text{v}\,\text{=}\,\text{2f}\,\text{(}{{\text{l}}_{\text{2}}}\text{-}{{\text{l}}_{\text{1}}}\text{)}\] \[\text{v}=2\times 480\times \left( 7030 \right)\times {{10}^{2}}\] \[\text{v}=960\times 40\times {{10}^{2}}\] \[\text{v}=38400\times {{10}^{2}}m/s\] \[\text{v}=384\text{ }m/s\]


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