A) \[124{}^\text{o}C,62{}^\text{o}C\]
B) \[37{}^\text{o}C,99{}^\text{o}C\]
C) \[62{}^\text{o}C,124{}^\text{o}C\]
D) \[99{}^\text{o}C,37{}^\text{o}C\]
Correct Answer: B
Solution :
Efficiency of Carnot engine \[=1-\frac{{{T}_{\sin k}}}{{{T}_{source}}}\] Given, \[\frac{1}{6}=1-\frac{{{T}_{\sin k}}}{{{T}_{source}}}\Rightarrow \frac{{{T}_{\sin k}}}{{{T}_{source}}}=\frac{5}{6}\] .....(1) Also, \[\frac{2}{6}=1-\frac{{{T}_{\sin k}}-62}{{{T}_{source}}}\Rightarrow \frac{62}{{{T}_{source}}}=\frac{1}{6}\] ?..(2) \[\therefore \]\[{{T}_{source}}=372K={{99}^{o}}C\] Also, \[{{T}_{\operatorname{sink}}}=\frac{5}{6}\times 372=310K={{37}^{o}}C\] (Note :- Temperature of source is more than temperature of sink)
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