JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Morning)

  • question_answer
    The value of r for which \[^{20}C{{r}^{20}}{{C}_{0}}{{+}^{20}}{{C}_{r-1}}^{20}{{C}_{1}}\]\[{{+}^{20}}{{C}_{r-2}}^{20}{{C}_{2}}+....{{+}^{20}}{{C}_{0}}^{20}{{C}_{r}}\]is maximum, is [JEE Main Online Paper (Held On 11-Jan-2019 Morning]

    A) 20                                

    B)               10   

    C)               15                                            

    D)               11

    Correct Answer: A

    Solution :

    The coefficient of\[{{x}^{2}}\]in the expansion of\[{{(1+x)}^{20}}{{(1+x)}^{20}}\]is\[^{20}{{C}_{r}}^{20}{{C}_{0}}{{+}^{20}}{{C}_{r-1}}^{20}{{C}_{1}}{{+}^{20}}{{C}_{r-2}}\]\[^{20}{{C}_{2}}+...{{+}^{20}}{{C}_{0}}^{20}{{C}_{r}},\]which is the given sum. Now, coefficient of \[{{x}^{r}}\] in \[{{(1+x)}^{40}}\]is \[^{40}{{C}_{r}}.\] Here, n = 40 and coefficient of\[{{x}^{r}}\] will be maximum when \[r=\frac{n}{2}=\frac{40}{2}=20.\]


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