JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Evening)

  • question_answer
    \[A\xrightarrow[{}]{4KOH,{{O}_{2}}}\underset{(green)}{\mathop{2B}}\,+2{{H}_{2}}O\] \[3B\xrightarrow[{}]{4HCl}\underset{(purple)}{\mathop{2C}}\,+Mn{{O}_{2}}+2{{H}_{2}}O\] \[2C\xrightarrow[{}]{{{H}_{2}}O,KI}2A+2KOH+D\] In the above sequence of reactions, A and D, respectively are [JEE  Main Online Paper (Held on 11-jan-2019 Evening)]

    A) \[KI\]and\[KMn{{O}_{4}}\]                    

    B) \[KI{{O}_{3}}\]and\[Mn{{O}_{2}}\]

    C) \[KI\]and\[{{K}_{2}}Mn{{O}_{4}}\]      

    D)   \[Mn{{O}_{2}}\]and\[KI{{O}_{3}}\]

    Correct Answer: D

    Solution :

    \[\underset{(A)}{\mathop{2Mn{{O}_{2}}}}\,+4KOH+{{O}_{2}}\to \underset{Green\,(B)}{\mathop{2{{K}_{2}}Mn{{O}_{4}}}}\,+2{{H}_{2}}O\] \[3{{K}_{2}}Mn{{O}_{4}}+4HCl\to \underset{Purple\,(C)}{\mathop{2KMn{{O}_{4}}}}\,+Mn{{O}_{2}}+2{{H}_{2}}O\] \[2KMn{{O}_{4}}+{{H}_{2}}O+KI\to 2KOH+\underset{(A)}{\mathop{2Mn{{O}_{2}}}}\,+\underset{(D)}{\mathop{KI{{O}_{3}}}}\,\]


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