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JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Evening)

  • question_answer
    The coordination number of Th in\[{{K}_{4}}[Th{{({{C}_{2}}{{O}_{4}})}_{4}}{{(O{{H}_{2}})}_{2}}]\]is                      \[({{C}_{2}}O_{4}^{2-}=oxalato)\] [JEE  Main Online Paper (Held on 11-jan-2019 Evening)]

    A) 8                                             

    B) 10

    C) 14                                

    D)   6

    Correct Answer: B

    Solution :

    Oxalato \[({{C}_{2}}O_{4}^{2-})\]is a bidentate and \[{{H}_{2}}O\]is unidentate ligand.


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