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JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Evening)

  • question_answer
    In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = K, where K is a constant. In this process, the temperature of the gas is increased by \[\Delta T\]. The amount of heat absorbed by gas is (R is gas constant) [JEE  Main Online Paper (Held on 11-jan-2019 Evening)]

    A) \[\frac{2K}{3}\Delta T\]                         

    B) \[\frac{1}{2}R\Delta T\]

    C) \[\frac{3}{2}R\Delta T\]             

    D)   \[\frac{1}{2}KR\Delta T\]

    Correct Answer: B

    Solution :

    \[VT=K,V\left( \frac{PV}{R} \right)=K\] or\[P{{V}^{2}}=\] constant For a poly tropic process \[C=\frac{R}{1-x}+{{C}_{V}}=\frac{R}{1-2}+\frac{3R}{2}=\frac{R}{2}\] \[\therefore \]\[\Delta Q=nC\Delta T=\frac{1}{2}R\Delta T\]


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