A) \[{{[CoC{{l}_{6}}]}^{4-}}\]
B) \[{{[CoC{{l}_{6}}]}^{3-}}\]
C) \[{{[CoC{{l}_{4}}]}^{2-}}\]
D) \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{2+}}\]
Correct Answer: C
Solution :
\[{{\left[ COC{{l}_{4}} \right]}^{2-}}\] reaction \[{{\left[ CO\underset{pink}{\mathop{{{\left( {{H}_{2}}O \right)}_{6}}}}\, \right]}^{2+}}+4C{{l}^{-}}\to {{\left[ CO\underset{Blue}{\mathop{{{\left( Cl \right)}_{4}}}}\, \right]}^{2-}}+6{{H}_{2}}O\,\text{pink}\]
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