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JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

  • question_answer
    \[A+2B\to C,\]the rate equation for this reaction is given as Rate=k[A][B]. If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself? [JEE Main Online Paper (Held On 11 April 2015)]  

    A)  halved

    B)  the same

    C)  doubled

    D)  quadrupled

    Correct Answer: B

    Solution :

    \[A+2B\to C\] \[\left( {{R}_{1}} \right)\text{Rate}\,=K\left[ A \right]\left[ B \right]\] ?..(1) According to condition \[\left( {{R}_{2}} \right)\text{Rate}\,=K\left[ A \right]\left[ 2B \right]\] ?... 2 equation \[eq2\div eq1\] \[\frac{{{R}_{2}}}{{{R}_{1}}}=2\] \[\]


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