question_answer

In the reaction of formation of sulphur trioxide by contact process \[2S{{O}_{2}}+{{O}_{2}}\rightleftharpoons 2S{{O}_{3}}\]the rate of reaction was measured as\[\frac{d\left[ {{O}_{2}} \right]}{dt}=-2.5\times {{10}^{-4}}\text{mol}\]\[\,{{L}^{-1}}{{s}^{-1}}.\]  The rate of reaction is terms of \[[S{{O}_{2}}]\]in mol \[{{\text{L}}^{\text{-1}}}\,{{\text{s}}^{\text{-1}}}\] will be:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )

A) \[-1.25\times {{10}^{-4}}\]                          

B) \[-2.50\times {{10}^{-4}}\]

C) \[-3.75\times {{10}^{-4}}\]                          

D) \[-5.00\times {{10}^{-4}}\]