A) \[35.2\times {{10}^{-10}}J/{{m}^{3}}\]
B) \[35.2\times {{10}^{-11}}J/{{m}^{3}}\]
C) \[35.2\times {{10}^{-12}}J/{{m}^{3}}\]
D) \[35.2\times {{10}^{-13}}J/{{m}^{3}}\]
Correct Answer: C
Solution :
Given: Amplitude of electric field, \[{{E}_{0}}=4v/m\] Absolute permitivity, \[{{\varepsilon }_{0}}=8.8\times {{10}^{-12}}{{c}^{2}}/N-{{m}^{2}}\] Average energy density \[{{u}_{E}}=?\] Applying formula, Average energy density\[{{u}_{E}}=\frac{1}{4}{{\varepsilon }_{0}}{{E}^{2}}\] \[\Rightarrow \]\[{{u}_{E}}=\frac{1}{4}\times 8.8\times {{10}^{-12}}\times {{(4)}^{2}}\] \[=35.2\times {{10}^{-12}}J/{{m}^{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
