JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Morning)

  • question_answer
    If the line \[3x+4y-24=0\] intersects the x-axis at the point A and the y-axis at the point B, then the in centre of the triangle OAB, where 0 is the origin, is- [JEE Main Online Paper (Held On 10-Jan-2019 Morning]

    A) (3, 4)                            

    B) (2, 2)

    C) (4, 4)    

    D)                  (4, 3)

    Correct Answer: B

    Solution :

      Circle C(r, r), radius r,  \[3x+4y-24=0\] tangent \[p=r\] \[\left| \frac{3r+4r-24}{5} \right|\,\,=\,\,r\] \[\left| 7r\,\text{-}\,24 \right|=5r\] \[7r-24=\pm \,5r\text{ };\text{ }r\,\,=\,\,6\,\,(not\,\,possible);\,\,r=2\] centre (2, 2)


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