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JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Morning)

  • question_answer
    The plane passing through the point \[\left( 4,\,\,-1,\text{ }2 \right)\] and parallel to the lines \[\frac{x+2}{3}\,\,=\,\frac{y-2}{-1}\,\,=\,\,\frac{z+1}{2}\] and \[\frac{x-2}{1}\,\,=\,\frac{y-3}{2}\,\,=\,\,\frac{z-4}{3}\] also passes through [JEE Main Online Paper (Held On 10-Jan-2019 Morning]

    A) (1, 1, -1)                                   

    B) (1, 1, 1)

    C) (-1, -1, -I)          

    D)                  (-1, -1, 1)

    Correct Answer: B

    Solution :

    Normal of plane \[=\,\,\,\left| \begin{matrix}    \widehat{i}  \\    3  \\    1  \\ \end{matrix}\,\,\,\,\,\,\begin{matrix}    \widehat{j}  \\    -1  \\    2  \\ \end{matrix}\,\,\,\,\,\,\begin{matrix}    \widehat{k}  \\    2  \\    3  \\ \end{matrix} \right|\,\,\,\,\,\] \[=\,\,\,\,\widehat{i}(-3-4)-\widehat{j}(9-2)+\widehat{k}(6+1)\] \[=\,\,-7\widehat{i}\,-7\widehat{j}\,+\,7\widehat{k}\] D.r.s of normal of plane = 1, 1, -1 Eq. of plane \[1(x-4)+1(y+1)-1(z-2)=0\] \[x+y-z-1=0\] Option point (1, 1, 1) satisfy it


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