A) \[{{O}^{2}}\]
B) \[{{N}^{+}}_{2}\]
C) \[{{O}^{+}}_{2}\]
D) \[{{N}_{2}}\]
Correct Answer: B
Solution :
\[{{N}^{+}}_{2}\left( {{13}^{e-}} \right)=\sigma 1{{s}^{2}},\,{{\sigma }^{*}}1{{s}^{2}},\text{ }\sigma 2{{s}^{2}},\text{ }{{o}^{*}}2{{S}^{2}},\,\pi 2p{{x}^{2}}\] \[=\pi 2{{p}_{y}}^{2}\,\sigma 2{{p}^{\text{1}}}_{\text{z}}\] \[{{N}^{+}}_{2}\Rightarrow BO\Rightarrow 2.5\Rightarrow \] \[[\pi -bond=2,\,\,\sigma \,\,bond=\frac{1}{2}]\] Similarly \[{{N}_{2}}\Rightarrow BO\Rightarrow 3\Rightarrow \,[\pi -bond=2,\,\,\sigma \,\,bond=1]\] \[{{O}^{+}}_{2}\Rightarrow BO\Rightarrow 2.5\Rightarrow \,\,[\pi -bond=1.5,\,\,\sigma \,\,bond=1]\]\[{{O}_{2}}\Rightarrow \,BO\Rightarrow 2\Rightarrow \,\,[\pi -bond=1,\,\,\sigma \,\,bond=1]\]
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