JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Evening)

  • question_answer
    The tangent to the curve, \[y=x{{e}^{{{x}^{2}}}}\]passing through the point (1, e) also passes through the point

    A) \[\left( \frac{4}{3},\,\,\,2e \right)\]                        

    B) \[\left( 3,\,\,\,6e \right)\]

    C) \[\left( 2,\,\,3e \right)\]     

    D)                  \[\left( \frac{5}{3},\,\,2e \right)\]

    Correct Answer: A

    Solution :

    \[\frac{dy}{dx}\,=\,{{e}^{{{x}^{2}}}}\,+\,x{{e}^{{{x}^{2}}}}\,.\,2x\] At \[x=1\], slope of tangent \[m=3e\] Equation of tangent: \[y-e=3e\left( x-1 \right)\] \[\Rightarrow \,\,\,y=3ex-2e\] \[\left( \frac{4}{3},\,\,2e \right)\] lies on it


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