A) hcp lattice - A, \[\frac{1}{3}\] Tetrahedral voids - B
B) hcp lattice - B, \[\frac{1}{3}\] Tetrahedral voids - A
C) hcp lattice - A, \[\frac{2}{3}\] Tetrahedral voids - B
D) hcp lattice -B, \[\frac{2}{3}\] Tetrahedral voids - A
Correct Answer: B
Solution :
Total effective atoms in HCP unit cell = 6 Total no. of tetrahedral voids = 12 If B is placed at HCP lattice points then \[\frac{1}{3}\] of tetrahedral voids will be occupied by A. So the general formulae becomes\[{{A}_{2}}{{B}_{3}}\].
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