JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Evening)

  • question_answer
    For an elementary chemical reaction; \[{{A}_{2}}\,\,2{{A}_{1}}\], the expression for \[\frac{d[A]}{dt}\] is [JEE Main Online Paper (Held On 10-Jan-2019 Evening]

    A) \[2{{K}_{1}}\left[ {{A}_{2}} \right]-{{K}_{-1}}{{[A]}^{2}}\]               

    B) \[{{K}_{1}}\left[ {{A}_{2}} \right]-{{K}_{-1}}{{[A]}^{2}}\]

    C) \[{{K}_{1}}\left[ {{A}_{2}} \right]+{{K}_{-1}}{{[A]}^{2}}\]

    D)                  \[2{{K}_{1}}\left[ {{A}_{2}} \right]-2{{K}_{-1}}{{[A]}^{2}}\]

    Correct Answer: D

    Solution :

    \[\frac{d[A]}{dt}\,=\,2{{K}_{1}}[{{A}_{2}}]\,-\,2{{K}_{-1}}{{[A]}^{2}}\]


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