A) 153
B) 306
C) 612
D) 204
Correct Answer: B
Solution :
\[{{a}_{1}},{{a}_{2}},{{a}_{3}}\,...........\,{{a}_{n}}\,...........\,\] are in A.P. \[{{a}_{3}}+{{a}_{15}}={{a}_{7}}+{{a}_{11}}={{a}_{1}}+{{a}_{17}}=36\] sum of first 17 term \[=\frac{17}{2}({{a}_{1}}+{{a}_{17}})\] \[=\frac{17}{2}\times 36\] \[=17\times 18\] \[=306\]
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