2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held On 10 April 2015)

  • question_answer
    If the tangent to the conic,\[y-6={{x}^{2}}\]at (2, 10) touches the circle, \[{{x}^{2}}+{{y}^{2}}+8x-2y=k\](for some fixed k) at a point \[(\alpha ,\beta );\] then \[(\alpha ,\beta )\]is : JEE Main Online Paper (Held On 10 April 2015)

    A) \[\left( -\frac{7}{17},\frac{6}{17} \right)\]                            

    B) \[\left( -\frac{8}{17},\frac{2}{17} \right)\]

    C) \[\left( -\frac{4}{17},\frac{1}{17} \right)\]                            

    D) \[\left( -\frac{6}{17},\frac{10}{17} \right)\]

    Correct Answer: B

    Solution :

                     \[{{x}^{2}}-y+6=0\] \[2x-\left( \frac{y+10}{2} \right)+6=0\] \[4x-y-10+12=0\]centre of circle (- 4 , 2) \[\frac{x+4}{4}=\frac{y-2}{-1}=-\frac{(16-2+2)}{17}\] \[\left( \frac{-8}{17},\frac{2}{17} \right)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner