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JEE Main & Advanced JEE Main Paper (Held On 10 April 2015)

  • question_answer
    The value of \[\sum\limits_{r=16}^{30}{(r+2)(r-3)}\]is equal to : JEE Main Online Paper (Held On 10 April 2015)

    A)  7785                     

    B)  7775

    C)  7780                     

    D)  7770

    Correct Answer: C

    Solution :

                    \[\sum\limits_{r=16}^{20}{\left( {{r}^{2}}-r-6 \right)}=7780\]


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