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JEE Main & Advanced JEE Main Paper (Held On 10 April 2015)

  • question_answer
    If Rolle's theorem holds for the function \[f(x)=2{{x}^{3}}+b{{x}^{2}}+cx,x\in [-1,1],\]at the point \[x=\frac{1}{2},\]then 2b +c equals    JEE Main Online Paper (Held On 10 April 2015)

    A)  2

    B) - 1

    C)  -3

    D)  1

    Correct Answer: B

    Solution :

                     Conduction for Rolls theorem f(1) = f(-1) and\[f'\left( \frac{1}{2} \right)=0\] \[c=-2\]and\[b=\frac{1}{2}\]\[2b+c=-1\]


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