A) \[ns\to np\to (n-1)d\to (n-2)f\]
B) \[ns\to (n-1)d\to (n-2)f\to np\]
C) \[ns\to (n-2)f\to (n-1)d\to np\]
D) \[ns\to (n-2)f\to np\to (n-1)d\]
Correct Answer: C
Solution :
The sequence of filling electrons in sixth period : \[6s-4f-5d-6p\]i.e. \[\left( ns \right)\to \left( n-2 \right)f\to \left( n-1 \right)d\to np\]
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