question_answer

The geometry of \[XeO{{F}_{4}}\] by VSEPR theory is: JEE Main Online Paper (Held On 10 April 2015)

A)  octahedral

B)  pentagonal planar

C)  square pyramidal

D)  trigonal bipyramidal

Correct Answer: C

Solution :

                 In \[XeO{{F}_{4}},Xe\]is \[s{{p}^{3}}{{d}^{2}},\] hybridised having 5 Bond pairs & 1 lone pair  SHAPE: Square Pyramidal