A) 38
B) 98
C) 76
D) 64
Correct Answer: C
Solution :
\[{{a}_{1}}+{{a}_{4}}+{{a}_{7}}+{{a}_{10}}+{{a}_{13}}+{{a}_{16}}=114\] \[\Rightarrow \frac{6}{2}({{a}_{1}}+{{a}_{16}})=114\]\[\Rightarrow {{a}_{1}}+{{a}_{16}}=38\] So,\[{{a}_{1}}+{{a}_{6}}+{{a}_{11}}+{{a}_{16}}=\frac{4}{2}({{a}_{1}}+{{a}_{16}})\] \[=2\times 38=76\]
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