JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Morning)

  • question_answer The species that can have a trans-isomer is :
    (en = ethane 1, 2 diamine, ox = oxalate)
    [JEE Main 10-4-2019 Morning]

    A) \[[Pt(en)C{{l}_{2}}]\]                       

    B) \[{{[Cr{{(en)}_{2}}(ox)]}^{+}}\]

    C) \[[Zn(en)C{{l}_{2}}]\]                      

    D) \[{{[Pt{{(en)}_{2}}C{{l}_{2}}]}^{2+}}\]

    Correct Answer: D

    Solution :

    [a]no trans isomer possible because bidentate ligand will be co-ordinating only at \[90{}^\circ \]angle in square planar complex [b] no trans isomer possible [c] \[s{{p}^{3}}\] hybridized so no trans possible [d] trans and cis both are possible


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