JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Morning)

  • question_answer The major product of the following reaction is: \[C{{H}_{3}}\overset{\begin{smallmatrix}  OH \\  | \end{smallmatrix}}{\mathop{C}}\,HC{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\xrightarrow[triethyla\min e]{ehtyl\,formate\,(lequiv.)}\] [JEE Main 10-4-2019 Morning]

    A) \[C{{H}_{3}}\overset{\begin{smallmatrix}  OH \\  | \end{smallmatrix}}{\mathop{C}}\,HC{{H}_{2}}C{{H}_{2}}NHCHO\]

    B) \[C{{H}_{3}}CH=CH-C{{H}_{2}}N{{H}_{2}}\]

    C)

    D) \[C{{H}_{3}}-\overset{\begin{smallmatrix}  OH \\  | \end{smallmatrix}}{\mathop{C}}\,H-CH=C{{H}_{2}}\]

    Correct Answer: A

    Solution :

    \[C{{H}_{3}}-\overset{\begin{smallmatrix}  OH \\  | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{2}}-C{{H}_{2}}-N{{H}_{2}}\xrightarrow[triethyla\min e]{ethyl\,formate\,(lequiv.)}\]           \[C{{H}_{3}}-\overset{\begin{smallmatrix}  OH \\  | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{2}}-NH-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-H\] as \[N{{H}_{2}}\] is a better nucleophile than OH.


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