JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Morning)

  • question_answer In the given circuit, an ideal voltmeter connected across the \[10\Omega \]resistance reads 2V. The internal resistance r, of each cell is: [JEE Main 10-4-2019 Morning]

    A) \[1\Omega \]                           

    B) \[1.5\Omega \]

    C) \[0\Omega \]                           

    D) \[0.5\Omega \]

    Correct Answer: D

    Solution :

    \[{{R}_{eq}}=\frac{15\times 10}{25}+2+2r\]\[=8+2r\] \[i=\frac{3}{8+2r}\]           \[2=i\,{{R}_{eq}}=\frac{3}{8+2r}\times 6\] \[16+4r=18\]           \[\Rightarrow r=0.5\Omega \]  

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