• # question_answer In the given circuit, an ideal voltmeter connected across the $10\Omega$resistance reads 2V. The internal resistance r, of each cell is: [JEE Main 10-4-2019 Morning] A) $1\Omega$                           B) $1.5\Omega$C) $0\Omega$                           D) $0.5\Omega$

Solution :

${{R}_{eq}}=\frac{15\times 10}{25}+2+2r$$=8+2r$ $i=\frac{3}{8+2r}$           $2=i\,{{R}_{eq}}=\frac{3}{8+2r}\times 6$ $16+4r=18$           $\Rightarrow r=0.5\Omega$

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