A) \[1.3\text{ }{{m}^{2}}/Vs\]
B) \[1.5\text{ }{{m}^{2}}/Vs\]
C) \[1.8\text{ }{{m}^{2}}/Vs\]
D) \[1.0\text{ }{{m}^{2}}/Vs\]
Correct Answer: D
Solution :
\[\mu =\frac{{{V}_{d}}}{E}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,E=\rho J\] \[=\frac{1.1\times {{10}^{-3}}}{1.7\times {{10}^{-8}}\times \frac{5}{\pi \times 25\times {{10}^{-6}}}}\] \[=\frac{1.1\times {{10}^{-3}}\times \pi \times 25\times {{10}^{-6}}}{1.7\times {{10}^{-8}}\times 5}\approx 1.01{{m}^{2}}/Vs\]
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