JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Morning)

  • question_answer A moving coil galvanometer allows a full scale current of \[{{10}^{-4}}A\]. A series resistance of \[2M\Omega \] is required to convert the above galvanometer into a voltmeter of range 0-5 V. Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0-10 mA is : [JEE Main 10-4-2019 Morning]

    A) \[200\,\Omega \]                     

    B) \[100\,\Omega \]

    C) \[10\,\Omega \]                       

    D) None of these

    Correct Answer: D

    Solution :

    (Dropped) Bonus \[200+{{10}^{-4}}G=5\] So answer is Bonus


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