A) 220 V and 10A
B) 440 V and 5A
C) 440 V and 20 A
D) 220 V and 20 A
Correct Answer: B
Solution :
Given \[{{N}_{P}}=300,{{N}_{S}}=150,{{P}_{0}}=2200W\]\[{{I}_{S}}=10A\] \[{{P}_{0}}={{V}_{0}}{{I}_{0}}\Rightarrow 2200={{V}_{0}}\times 10\Rightarrow {{V}_{0}}=220V\] \[\because \frac{{{V}_{i}}}{{{V}_{0}}}=\frac{{{N}_{p}}}{{{N}_{s}}}\Rightarrow {{V}_{i}}=2\times 220=440V\] Also \[{{P}_{0}}={{V}_{i}}{{I}_{i}}\]\[\Rightarrow {{I}_{i}}=\frac{2200}{440}=5A\]
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