JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Morning)

  • question_answer A transformer consisting of 300 turns in the primary and 150 turns in the secondary gives output power of 2.2 kW. If the current in the secondary coil is 10A, then the input voltage and current in the primary coil are: [JEE Main 10-4-2019 Morning]

    A) 220 V and 10A           

    B) 440 V and 5A

    C) 440 V and 20 A          

    D) 220 V and 20 A

    Correct Answer: B

    Solution :

    Given \[{{N}_{P}}=300,{{N}_{S}}=150,{{P}_{0}}=2200W\]\[{{I}_{S}}=10A\]           \[{{P}_{0}}={{V}_{0}}{{I}_{0}}\Rightarrow 2200={{V}_{0}}\times 10\Rightarrow {{V}_{0}}=220V\]           \[\because \frac{{{V}_{i}}}{{{V}_{0}}}=\frac{{{N}_{p}}}{{{N}_{s}}}\Rightarrow {{V}_{i}}=2\times 220=440V\]             Also     \[{{P}_{0}}={{V}_{i}}{{I}_{i}}\]\[\Rightarrow {{I}_{i}}=\frac{2200}{440}=5A\]

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