• # question_answer Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are: [JEE Main 10-4-2019 Morning] A) $50\mu F\text{ }and\text{ }30\mu F$B)   $20\mu F\text{ }and\text{ }30\mu F$C) $60\mu F\text{ }and\text{ }40\mu F$D)   $40\mu F\text{ }and\text{ }10\mu F$

As q = CV Hence slope of graph will give capacitance. Slope will be more in parallel combination. Hence capacitance in parallel should be $50\mu F$& in series combination must be $8\mu F$. Only in option $40\mu F\text{ }\And \text{ }10\mu F$ ${{C}_{parallel}}=40+10=50\mu F$ ${{C}_{series}}=\frac{40\times 10}{40+10}=8\mu F$